Core 4.1 Units & Conversions

📏 SI Units & Conversions — T Level / Level 3 Engineering Maths

Every engineering measurement needs a unit. Using the wrong unit — or forgetting to convert — can cause catastrophic failure. From the NASA Mars orbiter crash (1999, caused by a metric/imperial mix-up!) to everyday workshop errors, units matter enormously.

T Level Core 4.1 7 SI base units Metric prefixes Imperial conversions Temperature scales
Two systemsMetric (SI) and Imperial — both still used in UK engineering
Metric (SI): mm, cm, m, km / g, kg, t
Imperial: inch, foot, yard, mile / oz, lb, ton

The metric system is used in science, engineering calculations and international trade. Imperial units are still common in construction, manufacturing and daily life in the UK — so engineers must handle both.

📌 In T Level exams you may be given a mix — always check the units in any question before calculating!
Why it mattersReal consequences of unit errors
  1. NASA Mars orbiter (1999) — crashed because one team used imperial, another metric. $327 million lost.
  2. Gimli Glider (1983) — Air Canada Boeing 767 ran out of fuel mid-flight: kg vs lbs confusion
  3. Workshop errors — machining a part in inches when the drawing is in mm produces scrap
  4. T Level exams — wrong units = wrong answer, even if the number is right
🔬SI Base Unitsthe 7 fundamentals
📏Prefixeskilo, milli, mega…
📐Metricwithin the system
🏴󠁧󠁢󠁥󠁮󠁧󠁿Imperialinches, feet, lbs
🔄Metric↔Imperialcross-system
🌡️Temperature°C, °F, K
⚙️Engineeringreal examples
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SI Base Units

The International System of Units (SI) has 7 base units. Every other unit in science and engineering is derived from these 7.

The 7 SI Base UnitsThese are the foundation of all measurement
m METRE Length symbol: m kg KILOGRAM Mass symbol: kg s SECOND Time symbol: s A AMPERE Electric current symbol: A K KELVIN Temperature symbol: K mol MOLE Amount of substance symbol: mol cd CANDELA Luminous intensity symbol: cd
📌 For T Level / Level 3 Engineering, you'll mostly use metre, kilogram, second and ampere. Kelvin appears in thermodynamics. Mole and candela are less common but you should know they exist.
Derived UnitsBuilt from the base units — the ones engineers use every day
Derived UnitSymbolWhat it measuresMade from…
NewtonNForcekg·m·s⁻²
PascalPaPressure / StressN/m² = kg·m⁻¹·s⁻²
JouleJEnergy / WorkN·m = kg·m²·s⁻²
WattWPowerJ/s = kg·m²·s⁻³
VoltVVoltageW/A = kg·m²·s⁻³·A⁻¹
OhmΩResistanceV/A = kg·m²·s⁻³·A⁻²
HertzHzFrequencys⁻¹ (cycles per second)
💡 Memory trick for Newton: F = ma → force = mass × acceleration → kg × m/s² → N = kg·m·s⁻²
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SI Prefixes

Prefixes scale any SI unit up or down by powers of 10. Learn these and you can handle any measurement from nanometres to gigawatts!

The Prefix ScaleFrom nano (×10⁻⁹) all the way to Giga (×10⁹)
n nano 10⁻⁹ 0.000000001 μ micro 10⁻⁶ 0.000001 m milli 10⁻³ 0.001 1 base unit 10⁰ m, kg, s, A… k kilo 10³ 1,000 M Mega 10⁶ 1,000,000 G Giga 10⁹ 1,000,000,000 ← SMALLER LARGER →
Full Prefix TableAll prefixes you need for T Level / Level 3 / Level 3 Engineering
PrefixSymbolMultiplierEngineering Example
nanon× 10⁻⁹ = 0.00000000145 nm — wavelength of UV light
microμ× 10⁻⁶ = 0.000001250 μm — human hair diameter
millim× 10⁻³ = 0.0013.5 mm — bolt thread pitch
centic× 10⁻² = 0.012.54 cm = 1 inch
(base)× 10⁰ = 11 m, 1 kg, 1 s
kilok× 10³ = 1,0004.5 kN — cable tension
MegaM× 10⁶ = 1,000,000200 MPa — steel yield stress
GigaG× 10⁹ = 1,000,000,000200 GPa — Young's modulus steel
Converting with prefixesAlways convert to base unit first
  1. Replace the prefix with its multiplier (e.g. k = × 1000)
  2. Multiply or divide to get the base unit
  3. Then convert to the target prefix if needed
4.7 kN → 4.7 × 1000 = 4700 N
250 μm → 250 × 10⁻⁶ = 0.00025 m
0.85 MW → 0.85 × 10⁶ = 850,000 W
Worked ExamplesPrefix conversions step by step
Convert 3.2 km to mm
km→m: 3.2 × 1000 = 3200 m
m→mm: 3200 × 1000 = 3,200,000 mm ✅
Convert 47 mA to A
milli→base: 47 × 10⁻³
Answer: 0.047 A ✅
📏 Try it — SI Prefix ConverterAny prefix to any prefix
👆Try: 4.7 kΩ → Ω · 47 mA → A · 2400 W → kW · 0.1 μF → pF
📐

Metric Conversions

Converting within the metric system — length, mass, area, volume and time. All based on powers of 10, so just multiply or divide.

Lengthkm ↔ m ↔ cm ↔ mm — multiply going right, divide going left
KILOMETRES km × 1000 ÷ 1000 METRES m × 100 ÷ 100 CENTIMETRES cm × 10 ÷ 10 MILLIMETRES mm
💡 Going right (→) = getting smaller units = multiply. Going left (←) = getting bigger units = divide.
Mass conversions
t × 1000 → kg × 1000 → g × 1000 → mg
t ←÷1000 kg ←÷1000 g ←÷1000 mg
1 tonne = 1000 kg   1 kg = 1000 g   1 g = 1000 mg
Convert 4.25 kg to g
kg → g: × 1000
Answer: 4250 g ✅
Area & Volume conversions⚠️ Trickiest — square and cube the conversion factor!
Area: 1 m² = 100² cm² = 10,000 cm²
Area: 1 cm² = 10² mm² = 100 mm²
Vol: 1 m³ = 100³ cm³ = 1,000,000 cm³
Vol: 1 litre = 1000 cm³ = 1000 ml
⚠️ 1 m = 100 cm but 1 m² ≠ 100 cm² — it's 10,000 cm²! Always square or cube the factor!
Time conversionsSeconds, minutes, hours, days — NOT powers of 10!
SECONDS s ÷60 → MINUTES min ÷60 → HOURS h ÷24 → DAYS d
📌 1 min = 60 s  |  1 hour = 60 min = 3600 s  |  1 day = 24 hours = 86,400 s
📐 Try it — Metric ConverterLength · Mass · Volume · Time
👆Try: 4.25 kg → g · 2500 mm → m · 1 hour → s · 5 litres → cm³
🏴󠁧󠁢󠁥󠁮󠁧󠁿

Imperial Units

Imperial units are still widely used in UK engineering, construction and everyday life. You must be able to recognise them and convert to metric.

Imperial Length
UnitAbbreviationRelationship
inchin or "base of small lengths
footft or '1 ft = 12 inches
yardyd1 yd = 3 ft = 36 in
milemi1 mile = 1760 yd = 5280 ft
💡 Memory: 12 inches in a foot (12 months, 12 hours — 12 is everywhere!)
Imperial Mass & Volume
UnitAbbrev.Relationship
ounceozbase of small mass
poundlb1 lb = 16 oz
stonest1 st = 14 lb
ton (imperial)t1 ton = 2240 lb
fluid ouncefl ozbase of volume
pintpt1 pint = 20 fl oz
gallongal1 gallon = 8 pints
⚠️ UK ton vs US ton: Imperial (UK) ton = 2240 lb. US "short ton" = 2000 lb. Metric tonne = 1000 kg ≈ 2205 lb. Always specify which "ton" you mean in engineering!
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Converting Between Metric & Imperial

The conversion factors you MUST know for T Level / Level 3 / Level 3 Engineering. Always write the factor as an equation, then multiply or divide.

MethodWrite: X units × conversion factor = Y units. Arrange to solve for what you need.
Visual ScaleHow imperial and metric lengths compare — shown as bars
1 inch = 2.54 centimetres 1 in 2.54 cm ← same length! 1 foot reference = 648px wide 1 foot = 30.48 centimetres (≈ 30 cm) 1 foot (12 inches) 30.48 cm (≈ the same length) 1 mile vs 1 kilometre (1 mile = 1.609 km) 1 mile 1 km (about 62% of a mile) ← remaining 0.609 km →
Conversion Reference TableThe key conversion factors — memorise these!
QuantityImperial → MetricMetric → Imperial
Length1 inch = 2.54 cm1 cm = 0.394 inches
Length1 foot = 30.48 cm = 0.305 m1 m = 3.281 feet
Length1 mile = 1.609 km1 km = 0.621 miles
Length1 yard = 0.914 m1 m = 1.094 yards
Mass1 ounce (oz) = 28.35 g1 g = 0.035 oz
Mass1 pound (lb) = 453.6 g = 0.454 kg1 kg = 2.205 lb
Mass1 imperial ton = 1016 kg1 tonne = 0.984 imp. ton
Volume1 pint = 568 ml1 litre = 1.76 pints
Volume1 gallon = 4.546 litres1 litre = 0.220 gallons
Convert 5 feet 8 inches to metres
Total inches: 5×12 + 8 = 68 inches
× 2.54: 68 × 2.54 = 172.72 cm
Answer: 1.727 m ✅
⚙️ Convert 3.5 kg to pounds (lbs)
Factor: 1 kg = 2.205 lb
Multiply: 3.5 × 2.205 = 7.7175
Answer: 7.72 lb (3 s.f.) ✅
🔄 Try it — Metric ↔ ImperialLength · Mass · Volume
👆Try: 5 ft → m · 3.5 kg → lb · 26.2 miles → km (marathon) · 1 gallon → L
🌡️

Temperature Conversions

Three scales — Celsius (°C), Fahrenheit (°F) and Kelvin (K). Engineers use all three depending on the application.

Three Temperature ScalesKey reference points shown visually
BOILING FREEZING °C Celsius 100°C boiling 37°C body temp 0°C freezing °F Fahrenheit 212°F boiling 98.6°F body 32°F freezing K Kelvin 373 K boiling 310 K body 273 K freezing Absolute zero: 0 K = −273.15°C = −459.67°F (below this diagram)
°C ↔ °F Formulas
°F = (°C × 9/5) + 32
°C = (°F − 32) × 5/9
Convert 25°C to °F
Formula: °F = (25 × 9/5) + 32
Calculate: (25 × 1.8) + 32 = 45 + 32
Answer: 77°F ✅
°C ↔ Kelvin
K = °C + 273.15
°C = K − 273.15
📌 Kelvin is used in thermodynamics formulas (e.g. ideal gas law: PV = nRT). Temperature differences are the same in K and °C — only the zero point shifts.
Convert 350°C to Kelvin
Formula: K = 350 + 273.15
Answer: 623.15 K ✅
🌡️ Try it — Temperature Converter°C · °F · K
👆Try: 25°C → °F · 350°C → K · 150°C → K (gas law) · 212°F → °C
💡 Quick memory: °C to K — just add 273. K to °C — just subtract 273. The 0.15 is only needed for high-precision work.
⚙️

Applications

Where this topic is used in engineering, manufacturing, maintenance and daily life.

⚙️

Units in Engineering

Every engineering calculation involves units. Here's where you'll actually need each conversion skill in your T Level and on the job.

🔩 Precision Machining

Drawings may mix inches and mm. CNC programs work in mm. A 3/8" drill bit = 3/8 × 25.4 = 9.525 mm. Thread pitch M8 = 1.25 mm = 1.25 × 0.0394 = 0.049 inches.

3/8" drill bit:
3 ÷ 8 = 0.375 inches
0.375 × 25.4 = 9.525 mm

M8 pitch = 1.25 mm
= 1.25 ÷ 25.4 = 0.0492"

⚡ Electrical Engineering

Voltage, current and resistance use SI prefixes constantly. A 4.7 kΩ resistor = 4700 Ω. A 100 μF capacitor = 0.0001 F.

4.7 kΩ = 4.7 × 10³ = 4700 Ω
47 mA = 47 × 10⁻³ = 0.047 A
V = IR = 0.047 × 4700
= 220.9 V

🏗️ Structural Engineering

Forces in kN, stresses in MPa or N/mm² (same thing!), Young's modulus in GPa. Unit consistency in stress calculations is critical.

Stress = Force ÷ Area
F = 4.5 kN = 4500 N
A = 300 mm²
σ = 4500 ÷ 300 = 15 N/mm²
= 15 MPa

🌡️ Thermodynamics

Heat engines, refrigerators and gas laws all use Kelvin. Thermal expansion coefficients use 1/°C or 1/K (same difference in change).

Ideal gas: PV = nRT
T must be in KELVIN
T = 150°C + 273 = 423 K

Expansion: ΔL = L × α × ΔT
ΔT same in °C or K
🔧 T Level Exam Style — Unit Consistency Check
Problem: Calculate the pressure (Pa) on a piston. Force = 2.4 kN, area = 0.008 m².
Convert: 2.4 kN = 2.4 × 1000 = 2400 N
Formula: P = F ÷ A = 2400 ÷ 0.008
Answer: P = 300,000 Pa = 300 kPa = 0.3 MPa ✅
⚙️ Try it — Engineering Unit ConverterForce · Pressure · Power · Speed
👆Try: 2.4 kN → N · 300000 Pa → kPa · 70 mph → m/s · 1 kWh → J
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Quick Fire Quiz

10 questions, instant feedback.

⚡ Quick Blitz

Score: 0Streak: 0 🔥Q 1/10
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📝

Practice Questions

15 questions in 3 tiers — T Level / Level 3 Engineering style with full working shown.

🟢 Tier 1 — Foundations
Q1
State the SI unit and symbol for: (a) force   (b) pressure   (c) power
[3]
(a) Newton (N)
(b) Pascal (Pa)
(c) Watt (W)
Q2
Convert: (a) 4.5 km to m   (b) 850 mm to m   (c) 2.3 cm to mm
[3]
(a) 4.5 × 1000 = 4500 m
(b) 850 ÷ 1000 = 0.85 m
(c) 2.3 × 10 = 23 mm
Q3
Convert: (a) 3.2 kg to g   (b) 750 g to kg
[2]
(a) 3.2 × 1000 = 3200 g
(b) 750 ÷ 1000 = 0.75 kg
Q4
Write the prefix and symbol for: (a) × 10⁻³   (b) × 10³   (c) × 10⁶
[3]
(a) milli, m
(b) kilo, k
(c) Mega, M
Q5
Convert 25°C to (a) Fahrenheit   (b) Kelvin
[3]
(a) °F = (25 × 9/5) + 32 = 45 + 32 = 77°F
(b) K = 25 + 273.15 = 298.15 K
🟡 Tier 2 — Core Skills
Q6
Convert 47 mA to amperes, then to μA.
[3]
47 mA = 47 × 10⁻³ = 0.047 A
0.047 A = 0.047 × 10⁶ μA = 47,000 μA
Q7
A component is 3.5 inches long. Convert to mm. (1 inch = 25.4 mm)
[2]
3.5 × 25.4 = 88.9 mm ✅
Q8
Convert 5 feet 4 inches to centimetres. (1 inch = 2.54 cm)
[3]
Total inches = 5×12 + 4 = 64 inches
64 × 2.54 = 162.56 cm ✅
Q9
Convert an area of 2.5 m² to cm².
[3]
Remember: 1 m = 100 cm, so 1 m² = 100² cm²
1 m² = 10,000 cm²
2.5 × 10,000 = 25,000 cm² ✅
Q10
Convert 350°F to Celsius.
[2]
°C = (350 − 32) × 5/9 = 318 × 5/9 = 1590/9 = 176.7°C ✅
🔴 Tier 3 — T Level Challenge
Q11
Calculate the stress on a bolt. Force = 8.5 kN, cross-sectional area = 50 mm². Express the answer in (a) N/mm²   (b) MPa   (c) Pa in standard form.
[5]
F = 8.5 kN = 8500 N
σ = F/A = 8500 ÷ 50 = 170 N/mm²
(a) 170 N/mm²
(b) 170 MPa (1 N/mm² = 1 MPa)
(c) 170 × 10⁶ Pa = 1.70 × 10⁸ Pa ✅
Q12
An engineer in the USA specifies a shaft diameter of 1.375 inches. The UK workshop works in mm. Convert to mm to 2 decimal places. (1 inch = 25.4 mm)
[3]
1.375 �
Q13
A steel bar is heated from 20°C to 680°C. The coefficient of linear thermal expansion is 12 × 10⁻⁶ /K. The bar is 2.4 m long. Calculate the extension in mm.
[4]
ΔT = 680 − 20 = 660 K
ΔL = L × α × ΔT
= 2.4 × 12×10⁻⁶ × 660
= 0.019008 m
= 19.0 mm ✅
Q14
A fuel tank holds 45 gallons. Calculate its capacity in (a) litres and (b) cm³. (1 gallon = 4.546 litres)
[4]
(a) 45 × 4.546 = 204.57 litres
(b) 204.57 × 1000 = 204,570 cm³ ✅
Q15
An electric motor outputs 2.2 kW at 1450 rpm. Calculate the shaft torque using T = P / ω where ω = 2πn/60. Show all unit conversions.
[5]
P = 2.2 kW = 2200 W
ω = 2π × 1450 ÷ 60 = 151.84 rad/s
T = 2200 ÷ 151.84
= 14.49 N·m ✅
🎯 Score guide: Q1–5 = foundations (14 marks) · Q6–10 = core skills (13 marks) · Q11–15 = T Level challenge (21 marks)
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