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๐Ÿงฑ

Prisms and Cuboids

A prism has a uniform cross-section along its length. The volume is always: cross-section area ร— length. Cuboids are rectangular prisms โ€” the most common shape in engineering.

๐Ÿ“ The Rules

V = A_cross ร— L
Cross-sectional area multiplied by the length of the prism.
SA = 2ร—A_cross + perimeter ร— L
Two end faces plus the rectangular side faces wrapped around.
cuboid = rectangular prism
Its cross-section is a rectangle, so V = l ร— w ร— h.

๐Ÿ“– Key Vocabulary

Prism โ€” a solid with the same cross-section all along its length.
Cuboid โ€” a prism with a rectangular cross-section.
Perimeter โ€” the total distance around the edge of the cross-section.
All prisms: V = Across ร— L    SA = 2ร—Across + perimeter ร— L
Cuboid formulas
Volume: V = l ร— w ร— h
SA = 2(lw + lh + wh)
Space diagonal: d = โˆš(lยฒ + wยฒ + hยฒ)
l=8cm, w=5cm, h=3cm. Find V, SA, diagonal.
V: 8ร—5ร—3 = 120 cmยณ
SA: 2(40+24+15) = 2ร—79 = 158 cmยฒ
Diagonal: โˆš(64+25+9) = โˆš98 = 9.90 cm
Triangular prism formulas
V = ยฝ ร— b ร— h ร— L (b=base, h=tri height, L=length)
SA = bL + 3sL + 2ร—(ยฝbh) (if equilateral)
More generally: SA = 2ร—(triangle area) + perimeterร—L
Right-angle triangle: legs 6,8cm, L=15cm.
Hypotenuse: โˆš(36+64) = 10 cm
V: ยฝร—6ร—8ร—15 = 360 cmยณ
SA: 2ร—(ยฝร—6ร—8) + (6+8+10)ร—15 = 48+360 = 408 cmยฒ
๐Ÿ’ก Any prism: identify the cross-section shape first, find its area and perimeter, then multiply by the length. Works for hexagonal, T-section, I-section, L-section prisms too.
โš™๏ธ

Cylinders and Cones

The cylinder is a circular prism. The cone holds exactly one-third the volume of a cylinder with the same base and height โ€” a fact you can verify by filling one with water into the other.

๐Ÿ“ The Rules

cylinder: V = ฯ€rยฒh
Circle area (ฯ€rยฒ) times the height.
cone: V = โ…“ฯ€rยฒh
One third of the matching cylinder's volume.
curved SA โ‰  total SA
Check whether the question wants just the curved surface or the whole shape including ends.

๐Ÿ“– Key Vocabulary

Cylinder โ€” a solid with two parallel circular ends joined by a curved surface.
Cone โ€” a solid that tapers from a circular base to a single apex point.
Curved surface area โ€” the area of the outer "tube" or "wrap", excluding the flat ends.
Slant height โ€” the distance from the base edge to the apex of a cone, along the surface.
Cylinder
V = ฯ€rยฒh
Curved SA = 2ฯ€rh (the tube)
Total SA = 2ฯ€rยฒ + 2ฯ€rh = 2ฯ€r(r+h)
r=6cm, h=20cm. Closed cylinder.
V: ฯ€ร—36ร—20 = 720ฯ€ = 2262 cmยณ
Curved SA: 2ฯ€ร—6ร—20 = 240ฯ€ = 753.9 cmยฒ
Total SA: 2ฯ€ร—6ร—(6+20) = 312ฯ€ = 980.2 cmยฒ
Cone
V = โ…“ฯ€rยฒh (= โ…“ ร— cylinder)
Slant height: l = โˆš(rยฒ + hยฒ)
Curved SA = ฯ€rl
Total SA = ฯ€rยฒ + ฯ€rl = ฯ€r(r+l)
r=5cm, h=12cm. Find V, l, SA.
Slant: l = โˆš(25+144) = โˆš169 = 13 cm
V: โ…“ฯ€ร—25ร—12 = 100ฯ€ = 314.2 cmยณ
Total SA: ฯ€ร—5ร—(5+13) = 90ฯ€ = 282.7 cmยฒ
โš ๏ธ Slant height l โ‰  h. Always use l=โˆš(rยฒ+hยฒ) for surface area. h is the vertical height, l is the length along the sloping surface.
๐ŸŒ

Spheres and Frustums

The sphere is the most compact shape โ€” smallest surface area for a given volume. The frustum is a cone with its top sliced off, common in engineering components like hoppers and reducer fittings.

๐Ÿ“ The Rules

sphere: V = 4ฯ€rยณ/3
Uses radius cubed โ€” no height needed, since a sphere has no flat base.
sphere: SA = 4ฯ€rยฒ
Exactly four times the area of the sphere's largest circular cross-section.
frustum = cone โˆ’ smaller cone
Find the volume of the full cone, then subtract the volume of the sliced-off tip.

๐Ÿ“– Key Vocabulary

Sphere โ€” a perfectly round solid where every surface point is the same distance from the centre.
Frustum โ€” a cone (or pyramid) with its top sliced off parallel to the base.
Great circle โ€” the largest possible circular cross-section through the centre of a sphere.
Sphere
V = 4ฯ€rยณ/3
SA = 4ฯ€rยฒ
Note: SA = 4 ร— (area of great circle)
Diameter = 18cm. Find V and SA.
r: d/2 = 9 cm
V: 4ฯ€ร—729/3 = 972ฯ€ = 3053 cmยณ
SA: 4ฯ€ร—81 = 324ฯ€ = 1018 cmยฒ
Frustum
V = ฯ€h(Rยฒ + Rr + rยฒ) / 3
Slant: l = โˆš(hยฒ + (Rโˆ’r)ยฒ)
SA = ฯ€(R+r)l + ฯ€Rยฒ + ฯ€rยฒ
R=10cm, r=6cm, h=8cm.
Slant: l=โˆš(64+(10-6)ยฒ)=โˆš(64+16)=โˆš80=8.94cm
V: ฯ€ร—8ร—(100+60+36)/3=ฯ€ร—8ร—196/3=1641 cmยณ
SA: ฯ€(16)ร—8.94+ฯ€ร—100+ฯ€ร—36=970 cmยฒ
๐ŸŽ›๏ธ

Interactive Shape Explorer

Choose a shape, adjust its dimensions, and see Volume and Surface Area update live.

๐Ÿ“ The Rules

pick the right formula for the shape
Each shape button loads its own volume and surface area formulas.
watch what changes and what doesn't
Notice which dimensions affect volume vs. surface area, and by how much.

๐Ÿ“– Key Vocabulary

Dimension โ€” a measurable length that defines a shape's size, e.g. radius, height, side length.
Live update โ€” the values recalculate instantly as you change a slider.

ℹ️ How to use: Click a shape button, then drag the sliders to change its dimensions. Volume, surface area and other values update live and the diagram redraws instantly.

๐ŸŽ›๏ธ Pick a shape and drag the sliders

โ€”
Volume
โ€”
Surface Area
โ€”
โ€”
โ€”
โ€”
Change the sliders to explore how volume and surface area scale with dimension.
๐Ÿ”ง

Composite Shapes

Real engineering components are rarely simple. A composite shape is made of two or more basic shapes combined or subtracted. Split, calculate each, then combine.

๐Ÿ“ The Rules

split into basic shapes
Break the composite solid into prisms, cylinders, cones etc. you already know.
volumes simply add (or subtract)
Total volume = sum of the parts, or subtract for a hole or cut-out.
watch hidden faces in SA
Surface area isn't a simple sum โ€” joined faces disappear from the total.

๐Ÿ“– Key Vocabulary

Composite shape โ€” a solid built from two or more basic shapes joined or combined.
Hidden face โ€” a surface that's joined to another shape and so isn't part of the outer surface area.
Net volume โ€” the total volume after subtracting any removed or hollow section.
Method: Split into basic shapes โ†’ find V and SA of each โ†’ add volumes, adjust SA for any hidden faces
Cylinder with hemispherical end

A pressure vessel: cylinder r=8cm, h=30cm, with a hemispherical cap on one end.

Find total volume and outer surface area
Cylinder V: ฯ€ร—64ร—30 = 1920ฯ€ cmยณ
Hemisphere V: ยฝร—4ฯ€ร—512/3 = 1024ฯ€/3 cmยณ
Total V: 1920ฯ€+1024ฯ€/3 = 7083ฯ€/3 = 7424 cmยณ
Cylinder curved: 2ฯ€ร—8ร—30 = 480ฯ€ cmยฒ
One flat end: ฯ€ร—64 = 64ฯ€ cmยฒ
Hemisphere SA: 2ฯ€ร—64 = 128ฯ€ cmยฒ
Total SA: (480+64+128)ฯ€ = 672ฯ€ = 2111 cmยฒ
๐Ÿ’ก The circle where cylinder meets hemisphere is NOT included in the surface area โ€” it's an internal join.
Cylinder with cone on top

A grain silo: cylinder r=4m, h=12m, with a conical roof r=4m, h=3m.

Total volume and outer surface area
Cylinder V: ฯ€ร—16ร—12 = 192ฯ€ mยณ
Cone V: โ…“ฯ€ร—16ร—3 = 16ฯ€ mยณ
Total V: 208ฯ€ = 653.5 mยณ
Cone slant: l=โˆš(16+9)=โˆš25=5m
Cone curved SA: ฯ€ร—4ร—5=20ฯ€ mยฒ
Cylinder curved: 2ฯ€ร—4ร—12=96ฯ€ mยฒ
Base disc: ฯ€ร—16=16ฯ€ mยฒ
Total SA: (20+96+16)ฯ€ = 132ฯ€ = 414.7 mยฒ
Hollow cylinder (annular prism / pipe)

Pipe: outer radius R=60mm, inner radius r=50mm (wall=10mm), length=2m=2000mm.

Volume of material (wall)
Outer V: ฯ€ร—3600ร—2000 = 7,200,000ฯ€ mmยณ
Inner V: ฯ€ร—2500ร—2000 = 5,000,000ฯ€ mmยณ
Wall V: 2,200,000ฯ€ = 6,912,000 mmยณ = 6912 cmยณ
Surface area (all surfaces)
Outer curved: 2ฯ€ร—60ร—2000 = 240,000ฯ€ mmยฒ
Inner curved: 2ฯ€ร—50ร—2000 = 200,000ฯ€ mmยฒ
Two annular ends: 2ร—ฯ€(3600-2500) = 2200ฯ€ mmยฒ
Total SA: 442,200ฯ€ = 1,389,300 mmยฒ
⚙️

Applications

Where this topic is used in engineering, manufacturing, maintenance and daily life.

๐Ÿ“– Key Vocabulary

Capacity โ€” the volume a container can hold, often given in litres.
Material estimate โ€” a volume or surface-area calculation used to work out how much material a job needs.
๐Ÿ—๏ธ

Engineering Applications of 3D Shapes

Every branch of Level 3 Engineering uses volume and surface area calculations. These are the most examined contexts.

๐Ÿ“ The Rules

volume โ†’ capacity
Volume calculations tell you how much a tank, container or mould can hold.
surface area โ†’ material cost
Surface area calculations tell you how much material, coating or insulation is needed.
convert units carefully
1 mยณ = 1000 litres โ€” check which unit the question actually wants.

๐Ÿ“– Key Vocabulary

Capacity โ€” the volume a vessel or container can hold.
Vessel โ€” an engineering term for a tank or container designed to hold liquid or gas.
Insulation โ€” a material layer that reduces heat loss, sized using the object's surface area.

๐Ÿ›ข๏ธ Storage Tank Design โ€” Cylindrical Vessel

Oil storage tanks are cylinders. Volume determines capacity; surface area determines material and insulation cost.

Tank: D=3.6m (r=1.8m), height=5.5m

V = ฯ€rยฒh = ฯ€ร—3.24ร—5.5 = 17.82ฯ€ = 55.97 mยณ
= 55,970 litres

Curved SA = 2ฯ€ร—1.8ร—5.5 = 19.8ฯ€ = 62.2 mยฒ
Two ends = 2ร—ฯ€ร—3.24 = 6.48ฯ€ = 20.4 mยฒ
Total SA = 82.6 mยฒ

Steel plate 6mm at 47.1kg/mยฒ:
Mass = 82.6ร—47.1 = 3890 kg

๐Ÿ”ฉ Turned Component โ€” Volume of Material

A stepped shaft has different diameters along its length. Total material volume = sum of cylinder volumes for each step.

Shaft: 3 sections
Section 1: d=80mm, L=120mm
Section 2: d=60mm, L=80mm
Section 3: d=40mm, L=60mm

Vโ‚ = ฯ€ร—40ยฒร—120 = 192,000ฯ€ mmยณ
Vโ‚‚ = ฯ€ร—30ยฒร—80 = 72,000ฯ€ mmยณ
Vโ‚ƒ = ฯ€ร—20ยฒร—60 = 24,000ฯ€ mmยณ
Total = 288,000ฯ€ = 904,779 mmยณ โ‰ˆ 905 cmยณ

Steel density 7.85g/cmยณ:
Mass = 905ร—7.85 = 7.1 kg

๐Ÿ—๏ธ Concrete Foundation โ€” Volume and Cost

A strip foundation for a building is a long rectangular prism. Pad foundations are cuboids or cylinders.

Strip foundation: 500mm wide, 300mm deep
Total length = 48m

Cross-section A = 0.5ร—0.3 = 0.15 mยฒ
V = 0.15ร—48 = 7.2 mยณ

Pad foundation (circular): r=0.6m, h=0.5m
V = ฯ€ร—0.36ร—0.5 = 0.18ฯ€ = 0.565 mยณ

Ready-mix concrete at ยฃ140/mยณ:
Strip total = 7.2ร—140 = ยฃ1,008

โš™๏ธ Sheet Metal Fabrication โ€” Unfolded Surface Area

A cylindrical duct is cut from sheet metal. The flat sheet area equals the curved surface area โ€” useful for material costing.

Duct: diameter=300mm, length=2.5m
r=150mm=0.15m

Curved SA = 2ฯ€rร—L = 2ฯ€ร—0.15ร—2.5
= 0.75ฯ€ = 2.356 mยฒ

Sheet metal at 7.5kg/mยฒ (1mm steel):
Mass = 2.356ร—7.5 = 17.7kg per length

For a cone reducer (R=200mmโ†’r=120mm, h=300mm):
Slant l = โˆš(300ยฒ+80ยฒ) = 310 mm
Curved SA = ฯ€(R+r)l = ฯ€ร—320ร—310 = 99,200ฯ€ mmยฒ
= 0.312 mยฒ

๐ŸŒก๏ธ Insulation โ€” Surface Area for Heat Loss

Heat loss through a surface is proportional to area. Engineers calculate total surface area of a vessel to size insulation.

Pressure vessel: cylinder r=0.5m, h=2m
+ two hemispherical ends

Cylinder curved: 2ฯ€ร—0.5ร—2 = 2ฯ€ mยฒ
Two hemispheres = 4ฯ€rยฒ = 4ฯ€ร—0.25 = ฯ€ mยฒ
Total SA = 3ฯ€ = 9.42 mยฒ

Heat loss: Q = Uร—Aร—ฮ”T
U=0.5 W/mยฒK, ฮ”T=60ยฐC:
Q = 0.5ร—9.42ร—60 = 282.6 W

With 50mm insulation (U=0.08):
Q = 0.08ร—9.42ร—60 = 45.2 W (84% reduction)

๐Ÿชฃ Hopper โ€” Frustum Volume and Flow

A hopper (bin bottom) is a frustum. Its volume determines storage; its slope angle determines whether material flows freely.

Hopper: R=1.2m, r=0.15m, h=1.8m

V = ฯ€h(Rยฒ+Rr+rยฒ)/3
= ฯ€ร—1.8ร—(1.44+0.18+0.0225)/3
= ฯ€ร—1.8ร—1.6425/3
= 0.9855ฯ€ = 3.096 mยณ

Slant: l=โˆš(1.8ยฒ+(1.2-0.15)ยฒ)=โˆš(3.24+1.1025)
=โˆš4.3425=2.084m

Curved SA: ฯ€(1.2+0.15)ร—2.084=ฯ€ร—1.35ร—2.084
= 2.813ฯ€ = 8.84 mยฒ
🧮

3D Shape Calculator

Choose any 3D shape, enter its dimensions, and get volume and surface area with every formula and step shown clearly.

๐Ÿ“ The Rules

pick the shape first
The input boxes change to match the dimensions that shape needs.
compare the working
Use the step-by-step output to check your own method.

๐Ÿ“– Key Vocabulary

Dimension โ€” a length measurement (radius, height, side, etc.) that defines a shape's size.
Working โ€” the step-by-step calculation shown alongside the final answer.
📦 Volume & Surface Area Calculator8 shapes with full working

ℹ️ How to use: Use the dropdown to pick a 3D shape. The input boxes update to match that shape. Type the dimensions and step-by-step working appears instantly.

Select a shape and enter the dimensions above.
👆 Try: Cube s=4 · Cylinder r=3, h=10 · Cone r=4, h=9 · Sphere r=6 · Frustum R=5, r=3, h=8
Volume formulas
Cube: V = s³
Cuboid: V = l × w × h
Cylinder: V = πr²h
Cone: V = ⅓πr²h
Sphere: V = &frac43;πr³
Prism: V = cross-section area × length
Surface area formulas
Cube: SA = 6s²
Cuboid: SA = 2(lw + lh + wh)
Cylinder: SA = 2πr² + 2πrh
Cone: SA = πr² + πrl  (l = slant height)
Sphere: SA = 4πr²
💡 Slant height l = √(r² + h²)
🎮

Quick Fire Quiz

Test your knowledge โ€” 10 questions, instant feedback.

⚡ 3D Shapes Blitz

ℹ️ How to play: A 3D shapes question appears. Click the correct answer. Score and streak update after each — click Next to continue.

Score: 0 Streak: 0 🔥 Q 1/10
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โœ๏ธ

Practice Questions

Always state the formula first, then substitute. Give exact answers in ฯ€ where appropriate, then convert to decimal.

๐ŸŸข Tier 1 โ€” Basic Shapes

ℹ️ How to use: Work through each question and write down your answer. When ready, click Show Answer for the full worked solution.

Q1
A cube has edge length 7cm. Find its volume and surface area.
[4]
V = 7ยณ = 343 cmยณ
SA = 6ร—49 = 294 cmยฒ
Q2
A cuboid measures 12cm ร— 8cm ร— 5cm. Find volume, surface area, and the longest diagonal.
[5]
V = 12ร—8ร—5 = 480 cmยณ
SA = 2(96+60+40) = 2ร—196 = 392 cmยฒ
d = โˆš(144+64+25) = โˆš233 = 15.26 cm
Q3
A cylinder has r=4.5cm and h=14cm. Find its volume and total surface area.
[4]
V = ฯ€ร—20.25ร—14 = 283.5ฯ€ = 890.6 cmยณ
SA = 2ฯ€ร—4.5ร—(4.5+14) = 9ฯ€ร—18.5 = 166.5ฯ€ = 523.1 cmยฒ
Q4
A cone has base diameter 16cm and vertical height 15cm. Find its volume, slant height and total surface area.
[5]
r=8cm
l=โˆš(64+225)=โˆš289=17cm
V=โ…“ฯ€ร—64ร—15=320ฯ€=1005 cmยณ
SA=ฯ€ร—8ร—(8+17)=200ฯ€=628.3 cmยฒ
Q5
A sphere has surface area 200ฯ€ cmยฒ. Find its radius and volume.
[4]
SA=4ฯ€rยฒ=200ฯ€ โ†’ rยฒ=50 โ†’ r=?
4ฯ€rยฒ=200ฯ€ โ†’ rยฒ=50 โ†’ r=โˆš50=7.07cm
V=4ฯ€ร—50โˆš50/3=200โˆš50ฯ€/3=1481 cmยณ
๐ŸŸก Tier 2 โ€” Engineering Problems
Q6
A steel tank is a cylinder, D=2.0m, h=4.5m. Find (a) volume in litres, (b) mass of steel if the plate is 8mm thick and density 7850 kg/mยณ.
[6]
(a) r=1m: V=ฯ€ร—1ร—4.5=4.5ฯ€=14.14 mยณ=14,140 litres
(b) SA=2ฯ€ร—1ร—(1+4.5)=11ฯ€=34.56mยฒ
Wall thickness=0.008m โ†’ volume of steel=34.56ร—0.008=0.277mยณ
Mass=0.277ร—7850=2174 kg
Q7
A concrete pile (cylinder) has d=400mm and length 8m. Find volume and mass (concrete density 2400 kg/mยณ).
[4]
r=0.2m: V=ฯ€ร—0.04ร—8=0.32ฯ€=1.005 mยณ
Mass=1.005ร—2400=2412 kg
Q8
A hopper (frustum) has R=0.8m, r=0.1m, h=1.2m. Find volume and slant surface area.
[5]
V=ฯ€ร—1.2ร—(0.64+0.08+0.01)/3=ฯ€ร—1.2ร—0.73/3=0.292ฯ€=0.917 mยณ
l=โˆš(1.44+(0.8-0.1)ยฒ)=โˆš(1.44+0.49)=โˆš1.93=1.389m
Curved SA=ฯ€(0.8+0.1)ร—1.389=ฯ€ร—0.9ร—1.389=1.25ฯ€=3.928 mยฒ
๐Ÿ”ด Tier 3 โ€” Composite & Challenge
Q9
A grain silo consists of a cylinder (r=3m, h=10m) with a hemispherical dome on top. Find total volume, and total external surface area (no floor).
[6]
Cylinder V=ฯ€ร—9ร—10=90ฯ€ mยณ
Hemisphere V=โ…”ฯ€ร—27=18ฯ€ mยณ
Total V=(90+18)ฯ€=108ฯ€=339.3 mยณ

Cylinder curved=2ฯ€ร—3ร—10=60ฯ€ mยฒ
Hemisphere SA=2ฯ€ร—9=18ฯ€ mยฒ
Total SA=(60+18)ฯ€=78ฯ€=245.0 mยฒ
Q10
A hollow steel shaft: outer d=120mm, inner d=80mm (bore), length=2.5m. Find (a) volume of steel, (b) mass at 7850 kg/mยณ, (c) total surface area including bore.
[7]
R=60mm=0.06m, r=40mm=0.04m
(a) V=ฯ€(Rยฒ-rยฒ)L=ฯ€(0.0036-0.0016)ร—2.5=ฯ€ร—0.002ร—2.5=0.005ฯ€=0.01571 mยณ
(b) Mass=0.01571ร—7850=123.3 kg
(c) Outer curved=2ฯ€ร—0.06ร—2.5=0.3ฯ€ mยฒ
Inner curved=2ฯ€ร—0.04ร—2.5=0.2ฯ€ mยฒ
Two annular ends=2ร—ฯ€(0.0036-0.0016)=0.004ฯ€ mยฒ
Total=0.504ฯ€=1.583 mยฒ
๐ŸŽฏ Score guide: Q1โ€“5 foundations (22 marks) ยท Q6โ€“8 engineering (15 marks) ยท Q9โ€“10 challenge (13 marks)
SkillLondon

SkillLondon โ€” Level 3 Engineering Maths  ยท  3D Shapes: Volume & Surface Area