AlgebraLogarithms
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📖 What is a Logarithm?

A logarithm answers: "What power must I raise the base to, to get this number?" It is the inverse of indices.

Inverse of indices logbase(answer) = power Decibels · pH · Signal gain
Two ways of writing the same fact INDICES FORM 2³ = 8 base² = answer │ power = 3 LOGARITHM FORM log₂(8) = 3 logbase(answer) = power
🎮 Base · Power · Answer Explorer

ℹ️ How to use: Click a Base button and a Power button below. The index form and logarithm form both update instantly so you can see they describe the same fact.

23 = 8
same fact — two forms
log2 (8) = 3
2^3 = 8  ↔  log₂(8) = 3 — "What power gives me 8 from base 2? Answer: 3"
🎮 Base · Power · Answer Explorer

ℹ️ How to use: Click a button for the base and a button for the power. Watch both the index form and logarithm form update live to show the same mathematical fact two ways.

2
3
23 = 8
↔️  log2(8) = 3
2³ = 8 ↔️ log₂(8) = 3 — "To get 8 from base 2, I need power 3"
Key facts
loga(a) = 1   (a¹ = a)
loga(1) = 0   (a⁰ = 1)
⚠ log(0) = ERROR  |  log(negative) = ERROR
💡 log button = log10  |  ln button = loge
Evaluate examples from your notes
(a) log₃(9)
3? = 9:3² = 9
Answer:log₃(9) = 2 ✓
(b) log₃(1/27)
Write:1/27 = 3−3
Answer:log₃(1/27) = −3 ✓
📐

Laws of Logarithms

Four laws derived from index laws. Learn them, then use the interactive matching game.

The four laws of logarithms LAW 1 PRODUCT log(xy) = log x + log y log 5 + log 10 = log 50 from a˜×a‹=a˜⁺‹ LAW 2 QUOTIENT log(x/y) = log x − log y log 10 − log 5 = log 2 LAW 3 POWER log(xᵐ) = m · log x log 10³ = 3 log 10 = 3 LAW 4 SPECIAL logₐ(1) = 0 logₐ(a) = 1 log 1=0   ln e=1   log 10=1

🔗 Rules Map — Tap an expression, then its simplified result

The law used is shown when you get it right!

Matched: 0 / 8
All four laws
Law 1:   log(xy) = log x + log y
Law 2:   log(x/y) = log x − log y
Law 3:   log(xᵐ) = m · log x
logₐ(1) = 0  |  logₐ(a) = 1
⚠ log(0) = ERROR always!
Worked examples
5 log 2 + 2 log 5
Law 3:log 32 + log 25
Law 1:log 800 ✓
log 10 + 2 log 3 − log 2
Law 4b:log 10 = 1
Laws 2+3:1 + log 9 − log 2 = log(10 × 4.5)
Answer:log 45 ✓
📈

Log Graphs

All log graphs pass through (1,0). Drag the slider to see how changing the base reshapes the curve.

y = loga(x):   passes through (1, 0)  |  passes through (a, 1)  |  defined x>0 only  |  asymptote x=0
2.0
y = log₂(x)  |  passes through (1, 0) and (2, 1)  |  log₂(4) = 2

🟡 fixed point at (1, 0)  ·  🟢 point at (base, 1)

Key points: log₂(x)
log₂(½) = −1   (2⁻¹ = 0.5)
log₂(1) = 0   (2⁰ = 1)
log₂(2) = 1   (2¹ = 2)
log₂(4) = 2   (2² = 4)
log₂(8) = 3   (2³ = 8)
Log is the inverse of exponential

The log graph is the reflection of y=ax in the line y=x. They undo each other:

ln(ex) = x   and   eln x = x
log(10x) = x   and   10log x = x
💡 Use this to solve equations where x is in a power.
✏️

Worked Examples

Applying the laws step by step. Always state which law you use.

Example 1 — Evaluate log₂(512)
Ask:2? = 512 → 2,4,8,16,32,64,128,256,512
Answer:log₂(512) = 9 ✓
Example 2 — Evaluate log₈(1/64)
Write:1/64 = 64−1 = (8²)−1 = 8−2
Answer:log₈(1/64) = −2 ✓
Example 3 — Simplify: 2 log 3 − 3 log 2
Law 3:log 9 − log 8
Law 2:log(9/8) ✓
Example 4 — Simplify: 5 log 2 + 4 log 3 − 3 log 4
Law 3:log 32 + log 81 − log 64
Laws 1+2:log(32×81/64)
Answer:log(81/2) ✓
Example 5 — Simplify: log 10 + 2 log 3 − log 2
Law 4b:log 10 = 1
Laws 2+3:1 + log 9 − log 2 = log 10 + log(9/2)
Answer:log 45 ✓
Example 6 — Simplify: log 12 − 2 log 2 + log 3
Law 3:log 12 − log 4 + log 3
Laws 1+2:log(12/4 × 3) = log(3×3)
Answer:log 9 ✓
🔧

Solving Equations Using Logs

When x is in the power, take logs of both sides and use Law 3 to bring it down.

Key method:   ax = b  ⇒  x log a = log b  ⇒  x = log b / log a
4-step method
  1. 1Take log of both sides
  2. 2Apply Law 3 — bring power to front
  3. 3Rearrange to isolate x
  4. 4Calculator for numerical answer
Worked: solve 3x = 5
Take log:log 3x = log 5
Law 3:x log 3 = log 5
Rearrange:x = log 5 / log 3
Answer:x = 1.465 ✓
Harder: solve 3x = 5x−2
Take log:x log 3 = (x−2) log 5
Expand:x log 3 = x log 5 − 2 log 5
Rearrange:2 log 5 = x(log 5 − log 3) = x log(5/3)
Answer:x = 2 log 5 / log(5/3) ✓
Solve 4x = 12
x log 4 = log 12x = 1.792 ✓
Solve ex = 8
Take ln:x = ln 8 = 2.079 ✓
💡 For base e: use ln directly.
🌍

Logarithms in Real Life & Engineering

Logarithms appear wherever quantities span enormous ranges — sound, earthquakes, signals, chemistry, finance and more.

🔊
Sound & Acoustics
Decibel Scale
dB = 10   log(I / I₀)
A sound 10× more intense is only +10 dB louder because your ear responds logarithmically. A jet engine (140 dB) is 1014 times more intense than the quietest sound you can hear.
⚗️
Chemistry & pH
Acidity Scale
pH = − log[H⁺]
Each pH unit = 10× more or less acidic. Stomach acid pH 1, pure water pH 7, bleach pH 13. The log scale makes the enormous range of concentrations manageable.
📡
Electronics & Signal Gain
Amplifiers & Filters
Gain (dB) = 20 log(V₀ᵘᵗ / Vᵖₙ)
Engineers use logs to compare signal voltages without needing huge numbers. A gain of 40 dB means the output is 100× the input voltage.
☢️
Radioactive Decay
Half-life & Carbon Dating
t = − ln(N / N₀) / λ
N = N₀ e−λt — to find when something decayed, take ln of both sides. Used in nuclear engineering and carbon-14 dating of ancient objects.
🌍
Earthquakes
Richter Scale
M = log(A / A₀)
Each step up the Richter scale = 10× more ground motion. A magnitude 7 quake is 1 000× stronger than magnitude 4 — but only 3 steps on the scale.
💰
Finance & Growth
Doubling Time & Compound Interest
t = ln(2) / r
At 7% annual growth: t = 0.693 / 0.07 ≈ 10 years to double. Logs turn exponential growth into a simple linear equation.
💡 The pattern: whenever a quantity can vary by millions or billions, engineers use a logarithmic scale to keep the numbers human-sized.
🧮

Interactive Logarithm Solver

Evaluate any logarithm, solve log equations, and apply the log laws step by step. Change the values and the working updates instantly.

📊 Log Evaluator — logb(x) = ?Step-by-step

ℹ️ How to use: Type a base and a number into the boxes. The tool calculates logb(x) and shows the connection back to index form.

log
(
)
Enter a base and number to evaluate.
👆 Try: log₂(8) · log₁₀(1000) · log₃(81) · log₅(0.04) · ln(e)
📐 Log Laws ExplorerLaws 1–4 with working

ℹ️ How to use: Enter two numbers A and B and a base, then use the dropdown to pick a log law. The full step-by-step simplification is shown.

Select a law from the dropdown to see the working.
👆 Try: log(4)+log(25) · log(100)−log(20) · 3 log(2) · log₂(2)
The 4 Laws at a Glance
Law 1   log(AB) = log A + log B
Law 2   log(A/B) = log A − log B
Law 3   log(Aⁿ) = n log A
Law 4a   logₐ(a) = 1
Law 4b   logₐ(1) = 0
Common mistakes
⚠ log(A+B) ≠ log A + log B
⚠ log(A×B) ≠ log A × log B
⚠ log(0) and log(negative) are undefined
✅ log without a base shown means log₁₀ on most calculators. ln means log𝑒 (natural log).
🎮

Games

Log Blitz to drill values, plus a Laws Match game.

⚡ LOG BLITZ — Evaluate the Logarithm

ℹ️ How to play: Click an expression on the left, then click its matching simplified form on the right. Correct pairs disappear — aim to match all 8 without mistakes.

Score: 0 Streak: 0 🔥 Q 1/10
log₂(8)

🔗 LAWS MATCH — Expression to Simplified Form

Tap left, then right

📝

Practice Questions

Show all working. State which law you use.

🟢 Tier 1 — Evaluate

ℹ️ How to use: Work through each question and write down your answer. When ready, click Show Answer to reveal the full worked solution and mark scheme.

Q1
Evaluate: (a) log₃(9)   (b) log₂(32)   (c) log₅(125)   (d) log₁₀(10000)
[4]
(a) 2   (b) 5   (c) 3   (d) 4
Q2
Evaluate: (a) log₄(64)   (b) log₂₅(5)   (c) log₃(1/27)   (d) log₈(2)
[4]
(a) 3   (b) 1/2   (c) −3   (d) 1/3
🟡 Tier 2 — Apply laws
Q3
Write as log N: (a) log 3 + log 5   (b) log 16 − log 2   (c) 3 log 4   (d) 2 log 3 − 3 log 2
[4]
(a) log 15   (b) log 8   (c) log 64   (d) log(9/8)
Q4
Simplify: (a) 5 log 2 + 2 log 5   (b) log 128 − 7 log 2   (c) log 10 + 2 log 3 − log 2
[3]
(a) log 800   (b) 0 (log 128 = 7 log 2)   (c) log 45
🔴 Tier 3 — Solve equations
Q5
Solve: (a) 10x = 5   (b) ex = 8   (c) 4x = 12   (d) 3x = 2
[4]
(a) 0.699   (b) 2.079   (c) 1.792   (d) 0.631
Q6
Solve 3x = 5x−2. Give answer to 3 d.p.
[5]
Hint: take log both sides, Law 3, rearrange, factorise
x log 3 = (x−2) log 5 ⇒ 2 log 5 = x log(5/3)
x = 2 log 5 / log(5/3) ≈ 4.301 ✓
🎯 Score: Q1–2 (8) · Q3–4 (7) · Q5–6 (9)

⏱ Timed Quiz — 15 seconds per question!

ℹ️ Timed Quiz: Each question gives you 15 seconds. Click the correct answer before time runs out — the timer ring shrinks as your time decreases. Your score and percentage are shown at the end.

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Logarithms