Algebra 3 of 6 Expanding Brackets
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( ) Expanding Brackets — Algebra 3

Expanding means removing brackets by multiplying out. It’s one of the most used skills in engineering algebra — every formula manipulation, every quadratic equation, every area calculation uses it.

Single brackets Double brackets (FOIL) Grid method Perfect squares Difference of two squares
Expanding means multiplying out to remove the brackets 3(2x + 5) EXPAND 6x + 15 No brackets — each term inside has been multiplied by 3
What is expanding?Removing brackets by multiplication

A bracket means “everything inside is multiplied by what’s outside”. Expanding means doing that multiplication to remove the bracket.

a(b + c) = ab + ac
(a + b)(c + d) = ac + ad + bc + bd
💡 Think of the distributive law: sharing the multiplication across every term inside. Like distributing sweets equally to everyone in a group!
📌 The result has the same value as the original — expanding just writes it in a different form (without brackets).
Why do engineers expand brackets?
  1. Solve equations — you must expand before you can collect like terms and solve
  2. Work with formulae — F = ma(1 + kt) needs expanding before substituting numbers
  3. Find areas & volumes — (L + 2)(W + 2) gives the expanded area of a bordered shape
  4. Prove relationships — showing two expressions are equal requires expanding both
⚠️ You cannot just “drop the brackets” — 3(2x + 5) ≠ 3 + 2x + 5. The 3 multiplies EVERY term inside!
1️⃣

Single Bracket

The simplest type — one term multiplied by everything inside a single bracket. Multiply each term inside by the term outside, one by one.

Rule: a(b + c) = ab + ac    Every term inside gets multiplied by the term outside.
3(2x + 5) — the 3 multiplies BOTH terms inside the bracket 3 ( 2x + 5 ) 3 × 2x = 6x 3 × 5 = 15 = 6x + 15 ✅
Step-by-step method
  1. Identify the term outside the bracket
  2. Multiply it by the first term inside — write the result
  3. Multiply it by the second term inside — write the result with the correct sign
  4. Continue for any further terms inside
  5. Simplify by collecting like terms if possible
✅ Always carry the sign of each term — if a term inside is negative, the result of multiplying it will be negative.
Worked Examples
Expand: 5(3x − 4)
5 × 3x: = 15x
5 × (−4): = −20
Answer: 15x − 20 ✅
Expand: x(x + 7)
x × x: = x²   (x×x = x²)
x × 7: = 7x
Answer: x² + 7x ✅
Expand and simplify: 3(2x + 1) + 2(x − 5)
First: 3(2x+1) = 6x + 3
Second: 2(x−5) = 2x − 10
Collect: 6x + 3 + 2x − 10
Answer: 8x − 7 ✅
⚠️ Most common mistake: Only multiplying the first term inside.
3(2x + 5) ≠ 6x + 5   ❌ (forgot to multiply the 5!)
3(2x + 5) = 6x + 15   ✅ (both terms multiplied)
2️⃣

Double Brackets

When two brackets are multiplied together, every term in the first bracket must multiply every term in the second. With two terms in each bracket, that gives us 4 multiplications.

Rule: (a + b)(c + d) = ac + ad + bc + bd    Every term from the first × every term from the second.
(x + 3)(x + 4) — each term in the first bracket multiplies each term in the second bracket x + 3 x + 4 F: x×x = x² O: x×4 = 4x I: 3×x = 3x L: 3×4 = 12
F = First    O = Outer    I = Inner    L = Last    Then collect: x² + 4x + 3x + 12 = x² + 7x + 12
Step-by-stepEvery multiplication listed clearly
  1. Multiply the first terms together
  2. Multiply the outer terms (first of bracket 1 × last of bracket 2)
  3. Multiply the inner terms (last of bracket 1 × first of bracket 2)
  4. Multiply the last terms together
  5. Collect like terms — the two middle terms usually combine
✅ The two middle terms (Outer and Inner) are always like terms and can be added together.
Worked Examples
Expand: (x + 5)(x + 2)
First: x × x = x²
Outer: x × 2 = 2x
Inner: 5 × x = 5x
Last: 5 × 2 = 10
Collect: x² + 7x + 10 ✅
Expand: (2x + 3)(x + 4)
First: 2x × x = 2x²
Outer: 2x × 4 = 8x
Inner: 3 × x = 3x
Last: 3 × 4 = 12
Collect: 2x² + 11x + 12 ✅
📐

The FOIL Method

FOIL is a memorable acronym for the order to do the 4 multiplications when expanding double brackets: First, Outer, Inner, Last.

FOIL for (x + 3)(x + 4) — four multiplications, then collect FIRST x × x = x² OUTER x × 4 = 4x INNER 3 × x = 3x LAST 3 × 4 = 12 ▼ Add all four results ▼ x² + 4x + 3x + 12 ▼ Collect like terms (4x + 3x = 7x) ▼ = x² + 7x + 12 ✅
Try it yourselfLive FOIL calculator

ℹ️ How to use: Type numbers into the four boxes to set up your double brackets (ax + b)(cx + d). The FOIL expansion and simplified answer update as you type.

(
coeff. of x
x +
constant
) (
coeff. of x
x +
constant
)
👆This builds the bracket pair (coeff×x + constant)(coeff×x + constant). Change any of the four boxes — the F/O/I/L steps and final answer update instantly. Leave "coeff. of x" as 1 for a plain x, or try 2, 3 etc. Try a −5 constant to see how negatives carry through.
FOIL ChecklistNever miss a multiplication
F → first term in ( ) 1 × first term in ( ) 2
O → first term in ( ) 1 × last term in ( ) 2
I → last term in ( ) 1 × first term in ( ) 2
L → last term in ( ) 1 × last term in ( ) 2
💡 After FOIL you always have 4 terms. Then collect like terms (usually the O and I terms combine) to get 3 terms.
Worked Examples
Expand: (x − 5)(x + 2)
F: x × x = x²
O: x × 2 = 2x
I: (−5) × x = −5x
L: (−5) × 2 = −10
Collect: x² − 3x − 10 ✅
Expand: (3x − 2)(2x + 5)
F: 3x × 2x = 6x²
O: 3x × 5 = 15x
I: (−2) × 2x = −4x
L: (−2) × 5 = −10
Collect: 6x² + 11x − 10 ✅

The Grid Method

The grid (or box) method is a visual alternative to FOIL. It’s brilliant for larger brackets and for students who prefer to see every multiplication laid out clearly. Every cell in the grid is one multiplication.

Grid method for (x + 3)(x + 4) — one cell = one multiplication x +4 x +3 x × x 4x x × 4 3x 3 × x 12 3 × 4 Collect all cells: x² + 4x + 3x + 12 4x + 3x = 7x, so: x² + 7x + 12 ✅
How to draw the grid
  1. Draw a 2×2 table (or larger for bigger brackets)
  2. Write the terms of the first bracket as column headers
  3. Write the terms of the second bracket as row headers
  4. Fill each cell by multiplying its row header × column header
  5. Add all cells together and collect like terms
💡 The grid method works for any size brackets — 3 terms in each? Use a 3×3 grid. It’s impossible to miss a term!
Worked Example(2x + 1)(3x + 5) using the grid
3x +5 2x +1 6x² 10x 3x 5 6x² + 10x + 3x + 5 6x² + 13x + 5 ✅

Special Cases

Two patterns appear so often in engineering algebra that they’re worth memorising. They save time and are tested directly in T Level exams.

Perfect Square(a + b)² = a² + 2ab + b²
(a + b)² shown as a square of side (a+b) ab ab a b a b Total area: (a+b)² = four cells: a² + ab + ab + b² a²+2ab+b² ✅
(a + b)² = a² + 2ab + b²
(a − b)² = a² − 2ab + b²    (middle term negative)
Expand (x + 4)²
a=x, b=4: a² + 2ab + b²
a²:
2ab: 2 × x × 4 = 8x
b²: 4² = 16
Answer: x² + 8x + 16 ✅
⚠️ Very common error: (x + 4)² ≠ x² + 16   ❌
The middle term 2ab = 8x is always there — never forget it!
Difference of Two Squares(a + b)(a − b) = a² − b²
(a + b)(a − b) = a² − b²
The middle terms cancel (+ab and −ab = 0). Only the squares remain!
(x+5)(x−5) — the middle terms always cancel + −5x + +5x + −25 cancels cancels = x² − 25
Expand (3x + 2)(3x − 2)
Pattern: a=3x, b=2  →  a² − b²
a²: (3x)² = 9x²
b²: 2² = 4
Answer: 9x² − 4 ✅

Negatives & Mixed Signs

Signs are where most students lose marks. A careful, consistent approach to negative terms prevents almost all errors.

The Sign RulesAlways apply these when multiplying
(+) × (+) = POSITIVE (+) × (−) = NEGATIVE (−) × (+) = NEGATIVE (−) × (−) = POSITIVE
💡 Same signs → positive. Different signs → negative.
This is the single most important rule to remember when expanding!
Negative outside the bracket
⚠️ A negative sign outside flips ALL signs inside!
−3(2x − 5)
= (−3)×2x + (−3)×(−5)
= −6x + 15
Expand −4(x − 3)
(−4)×x: = −4x
(−4)×(−3): = +12   (neg×neg=pos)
Answer: −4x + 12 ✅
Mixed signs in double brackets
Expand (x − 3)(x − 5)
F: x × x = x²
O: x × (−5) = −5x
I: (−3) × x = −3x
L: (−3)×(−5) = +15   ✔
Collect: x² − 8x + 15 ✅
Expand (2x − 3)²
Pattern: (a−b)² = a²−2ab+b²
a²: (2x)² = 4x²
2ab: 2×2x×3 = 12x
b²: 3² = 9
Answer: 4x² − 12x + 9 ✅
⚙️

Applications

Where this topic is used in engineering, manufacturing, maintenance and daily life.

🔨 Beam & Frame Dimensions

A rectangular steel frame has inner dimensions (x + 4) by (x + 3) metres. Find the area expression.

A = (x + 4)(x + 3)
= x² + 3x + 4x + 12
= x² + 7x + 12 m²

If x = 2m: A = 4 + 14 + 12 = 30 m²

⚡ Electrical Power

P = I²R. If I = (x + 2) amps and R = 3 ohms, expand to find the power expression.

P = (x + 2)² × 3
= 3(x² + 4x + 4)
= 3x² + 12x + 12 W

If x = 1: P = 3 + 12 + 12 = 27 W

🌡 Thermal Expansion

A square plate of side (L + ΔL) expands. Find the new area minus the original.

New area = (L + ΔL)²
= L² + 2LΔL + (ΔL)²
Increase = 2LΔL + (ΔL)²
≈ 2LΔL (for small ΔL)

📏 Pipe Cross-Section

Outer radius R, inner radius r. Wall area = π(R + r)(R − r) = π(R² − r²). Difference of two squares!

A = πR² − πr²
= π(R² − r²)
= π(R+r)(R−r)

If R=50mm, r=44mm:
A = π(94)(6) = 1772 mm²
🔧 T Level Exam Style — Expand and evaluate
Problem: A piston has diameter (2r + 3) mm. Find its cross-sectional area in terms of r, then evaluate when r = 5 mm.
Radius: (2r + 3)/2 — but area = π(radius)² — easier: use A = πd²/4
d²: (2r + 3)² = 4r² + 12r + 9
Area: A = π(4r² + 12r + 9) / 4
r=5: 4(25)+12(5)+9 = 100+60+9 = 169  →  A = 169π/4 ≈ 132.7 mm² ✅
🎮

Quick Fire Quiz

Test your knowledge — 10 questions, instant feedback.

⚡ Expanding Blitz

ℹ️ How to play: A question appears on screen. Click the answer you think is correct from the four options. Your score and streak update after each question. Click Next to move on.

Score: 0 Streak: 0 🔥 Q 1/10
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👆Click an answer button to lock it in — correct answers turn green, wrong ones turn red and reveal the right answer · Build a streak 🔥 by answering correctly in a row · Press Play Again after question 10 to reshuffle and try for a higher score.

Practice Questions

15 questions across 3 tiers. Try each one before revealing the answer — especially the sign rules!

🟢 Tier 1 — Foundations

ℹ️ How to use: Work through each question and write down your answer. When you are ready, click Show Answer to reveal the full worked solution and mark scheme.

Q1
Expand: 4(3x + 2)
[2]
4 × 3x = 12x
4 × 2 = 8
= 12x + 8
Q2
Expand: 5(2x − 7)
[2]
5 × 2x = 10x
5 × (−7) = −35
= 10x − 35
Q3
Expand: x(x + 6)
[2]
x × x = x²
x × 6 = 6x
= x² + 6x
Q4
Expand and simplify: 3(x + 4) + 2(x − 1)
[3]
3x + 12 + 2x − 2
Collect: = 5x + 10
Q5
Expand: −2(3x − 4)
[2]
Hint: negative × negative = positive
(−2) × 3x = −6x
(−2) × (−4) = +8
= −6x + 8
🟡 Tier 2 — Core Skills
Q6
Expand and simplify: (x + 4)(x + 6)
[3]
F=x² O=6x I=4x L=24
Collect: x² + 10x + 24
Q7
Expand and simplify: (x − 3)(x + 7)
[3]
F=x² O=7x I=−3x L=−21
Collect: x² + 4x − 21
Q8
Expand and simplify: (2x + 5)(3x − 2)
[3]
F=6x² O=−4x I=15x L=−10
Collect: 6x² + 11x − 10
Q9
Expand: (x + 7)²
[2]
Pattern (a+b)² = a²+2ab+b²: a=x, b=7
x² + 14x + 49
= x² + 14x + 49
Q10
Expand: (x + 9)(x − 9)
[2]
Difference of two squares: a²−b²
= x² − 81
= x² − 81
🔴 Tier 3 — T Level Challenge
Q11
Expand and simplify: (3x − 4)²
[3]
(a−b)² = a²−2ab+b²: a=3x, b=4
(3x)²=9x²   2(3x)(4)=24x   4²=16
= 9x² − 24x + 16
Q12
Expand and simplify: (x + 3)(x − 3) + (x + 2)²
[4]
(x+3)(x−3) = x² − 9
(x+2)² = x² + 4x + 4
Add: 2x² + 4x − 5
= 2x² + 4x − 5
Q13
A rectangular component has length (3x + 2) mm and width (2x − 1) mm. Write an expression for the area and simplify.
[3]
A = (3x+2)(2x−1)
F=6x² O=−3x I=4x L=−2
= 6x² + x − 2 mm²
Q14
Show that (5x + 3)(5x − 3) = 25x² − 9. What engineering formula does this pattern resemble?
[3]
Diff of 2 squares: (5x)² − 3² = 25x² − 9 ✅
Engineering: pipe wall area = π(R²−r²) = π(R+r)(R−r)
Same (a+b)(a−b) = a²−b² pattern ✅
Q15
Expand and simplify: 2(x + 3)² − 3(x − 1)(x + 4). State the type of expression you end up with.
[5]
2(x+3)² = 2(x²+6x+9) = 2x²+12x+18
(x−1)(x+4) = x²+3x−4
3(x−1)(x+4) = 3x²+9x−12
Subtract: 2x²+12x+18 − (3x²+9x−12)
= 2x²+12x+18 − 3x² − 9x + 12
= −x² + 3x + 30
This is a quadratic expression (highest power = 2)
🎯 Score guide: Q1–5 = foundations (11 marks) · Q6–10 = core skills (13 marks) · Q11–15 = T Level challenge (18 marks)

👉 Next topic: Factorising — the reverse process of expanding — putting brackets back in.
SL

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