Level 2 Engineering Maths Units & Conversions

📏 SI Units & Conversions — Level 2 Engineering Maths

Every engineering measurement needs a unit. Using the wrong unit — or forgetting to convert — can cause catastrophic failure. From the NASA Mars orbiter crash (1999, caused by a metric/imperial mix-up!) to everyday workshop errors, units matter enormously.

Level 2 Core Skill 7 SI base units Metric prefixes Imperial conversions Temperature scales

📋 Units — Quick Reference

1
Always check the units before you calculate
2
Metric moves in powers of 10; convert with the prefix chart
3
Metric ↔ Imperial needs a conversion factor
🧠

Key Words — What Do They Mean?

SI UnitThe standard
scientific unit
Prefixkilo, milli,
mega, etc
Conversion FactorNumber to multiply
or divide by
Two systemsMetric (SI) and Imperial — both still used in UK engineering
Metric (SI): mm, cm, m, km / g, kg, t
Imperial: inch, foot, yard, mile / oz, lb, ton

The metric system is used in science, engineering calculations and international trade. Imperial units are still common in construction, manufacturing and daily life in the UK — so engineers must handle both.

📌 In exams you may be given a mix — always check the units in any question before calculating!
Why it mattersReal consequences of unit errors
  1. NASA Mars orbiter (1999) — crashed because one team used imperial, another metric. $327 million lost.
  2. Gimli Glider (1983) — Air Canada Boeing 767 ran out of fuel mid-flight: kg vs lbs confusion
  3. Workshop errors — machining a part in inches when the drawing is in mm produces scrap
  4. Exams — wrong units = wrong answer, even if the number is right
🔬SI Base Unitsthe 7 fundamentals
📏Prefixeskilo, milli, mega…
📐Metricwithin the system
🏴󠁧󠁢󠁥󠁮󠁧󠁿Imperialinches, feet, lbs
🔄Metric↔Imperialcross-system
🌡️Temperature°C, °F, K
⚙️Engineeringreal examples
🔬

SI Base Units

The International System of Units (SI) has 7 base units. Every other unit in science and engineering is derived from these 7.

📋 SI Units — Quick Reference

1
7 base units: m, kg, s, A, K, mol, cd
2
Everything else is derived from these
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Key Words — What Do They Mean?

Base UnitA fundamental
building block
Derived UnitBuilt from base
units, e.g. m/s
The 7 SI Base UnitsThese are the foundation of all measurement
m METRE Length symbol: m kg KILOGRAM Mass symbol: kg s SECOND Time symbol: s A AMPERE Electric current symbol: A K KELVIN Temperature symbol: K mol MOLE Amount of substance symbol: mol cd CANDELA Luminous intensity symbol: cd
📌 For Level 2 Engineering, you'll mostly use metre, kilogram, second and ampere. Kelvin appears in thermodynamics. Mole and candela are less common but you should know they exist.
Derived UnitsBuilt from the base units — the ones engineers use every day
Derived UnitSymbolWhat it measuresMade from…
NewtonNForcekg·m·s⁻²
PascalPaPressure / StressN/m² = kg·m⁻¹·s⁻²
JouleJEnergy / WorkN·m = kg·m²·s⁻²
WattWPowerJ/s = kg·m²·s⁻³
VoltVVoltageW/A = kg·m²·s⁻³·A⁻¹
OhmΩResistanceV/A = kg·m²·s⁻³·A⁻²
HertzHzFrequencys⁻¹ (cycles per second)
💡 Memory trick for Newton: F = ma → force = mass × acceleration → kg × m/s² → N = kg·m·s⁻²
📏

SI Prefixes

Prefixes scale any SI unit up or down by powers of 10. Learn these and you can handle any measurement from nanometres to gigawatts!

📋 Prefixes — Quick Reference

1
kilo (k) = ×1000, milli (m) = ÷1000
2
Moving up the scale → divide. Moving down → multiply
🧠

Key Words — What Do They Mean?

PrefixGoes in front
of a unit
ScaleHow big or
small
The Prefix ScaleFrom nano (×10⁻⁹) all the way to Giga (×10⁹)
n nano 10⁻⁹ 0.000000001 μ micro 10⁻⁶ 0.000001 m milli 10⁻³ 0.001 1 base unit 10⁰ m, kg, s, A… k kilo 10³ 1,000 M Mega 10⁶ 1,000,000 G Giga 10⁹ 1,000,000,000 ← SMALLER LARGER →
Full Prefix TableAll prefixes you need for Level 2 Engineering
PrefixSymbolMultiplierEngineering Example
nanon× 10⁻⁹ = 0.00000000145 nm — wavelength of UV light
microμ× 10⁻⁶ = 0.000001250 μm — human hair diameter
millim× 10⁻³ = 0.0013.5 mm — bolt thread pitch
centic× 10⁻² = 0.012.54 cm = 1 inch
(base)—× 10⁰ = 11 m, 1 kg, 1 s
kilok× 10³ = 1,0004.5 kN — cable tension
MegaM× 10⁶ = 1,000,000200 MPa — steel yield stress
GigaG× 10⁹ = 1,000,000,000200 GPa — Young's modulus steel
Converting with prefixesAlways convert to base unit first
  1. Replace the prefix with its multiplier (e.g. k = × 1000)
  2. Multiply or divide to get the base unit
  3. Then convert to the target prefix if needed
4.7 kN → 4.7 × 1000 = 4700 N
250 μm → 250 × 10⁻⁶ = 0.00025 m
0.85 MW → 0.85 × 10⁶ = 850,000 W
Worked ExamplesPrefix conversions step by step
Convert 3.2 km to mm
km→m: 3.2 × 1000 = 3200 m
m→mm: 3200 × 1000 = 3,200,000 mm ✅
Convert 47 mA to A
milli→base: 47 × 10⁻³
Answer: 0.047 A ✅
📏 Try it — SI Prefix ConverterAny prefix to any prefix
→
👆Try: 4.7 kΩ → Ω · 47 mA → A · 2400 W → kW · 0.1 μF → pF
📐

Metric Conversions

Converting within the metric system — length, mass, area, volume and time. All based on powers of 10, so just multiply or divide.

📋 Metric Conversions — Quick Reference

1
Bigger unit → smaller unit: multiply
2
Smaller unit → bigger unit: divide
🧠

Key Words — What Do They Mean?

MetricBased on
powers of 10
ConvertChange to a
different unit
Lengthkm ↔ m ↔ cm ↔ mm — multiply going right, divide going left
KILOMETRES km × 1000 ÷ 1000 METRES m × 100 ÷ 100 CENTIMETRES cm × 10 ÷ 10 MILLIMETRES mm
💡 Going right (→) = getting smaller units = multiply. Going left (←) = getting bigger units = divide.
Mass conversions
t × 1000 → kg × 1000 → g × 1000 → mg
t ←÷1000 kg ←÷1000 g ←÷1000 mg
1 tonne = 1000 kg   1 kg = 1000 g   1 g = 1000 mg
Convert 4.25 kg to g
kg → g: × 1000
Answer: 4250 g ✅
Area & Volume conversions⚠️ Trickiest — square and cube the conversion factor!
Area: 1 m² = 100² cm² = 10,000 cm²
Area: 1 cm² = 10² mm² = 100 mm²
Vol: 1 m³ = 100³ cm³ = 1,000,000 cm³
Vol: 1 litre = 1000 cm³ = 1000 ml
⚠️ 1 m = 100 cm but 1 m² ≠ 100 cm² — it's 10,000 cm²! Always square or cube the factor!
Time conversionsSeconds, minutes, hours, days — NOT powers of 10!
SECONDS s ÷60 → MINUTES min ÷60 → HOURS h ÷24 → DAYS d
📌 1 min = 60 s  |  1 hour = 60 min = 3600 s  |  1 day = 24 hours = 86,400 s
📐 Try it — Metric ConverterLength · Mass · Volume · Time
→
👆Try: 4.25 kg → g · 2500 mm → m · 1 hour → s · 5 litres → cm³
🏴󠁧󠁢󠁥󠁮󠁧󠁿

Imperial Units

Imperial units are still widely used in UK engineering, construction and everyday life. You must be able to recognise them and convert to metric.

📋 Imperial Units — Quick Reference

1
Length: inch, foot, yard, mile
2
Mass: ounce, pound, stone, ton
🧠

Key Words — What Do They Mean?

ImperialThe older UK
unit system
Imperial Length
UnitAbbreviationRelationship
inchin or "base of small lengths
footft or '1 ft = 12 inches
yardyd1 yd = 3 ft = 36 in
milemi1 mile = 1760 yd = 5280 ft
💡 Memory: 12 inches in a foot (12 months, 12 hours — 12 is everywhere!)
Imperial Mass & Volume
UnitAbbrev.Relationship
ounceozbase of small mass
poundlb1 lb = 16 oz
stonest1 st = 14 lb
ton (imperial)t1 ton = 2240 lb
fluid ouncefl ozbase of volume
pintpt1 pint = 20 fl oz
gallongal1 gallon = 8 pints
⚠️ UK ton vs US ton: Imperial (UK) ton = 2240 lb. US "short ton" = 2000 lb. Metric tonne = 1000 kg ≈ 2205 lb. Always specify which "ton" you mean in engineering!
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Converting Between Metric & Imperial

The conversion factors you MUST know for Level 2 Engineering. Always write the factor as an equation, then multiply or divide.

📋 Metric ↔ Imperial — Quick Reference

1
Write the conversion factor as an equation first
2
1 inch ≈ 2.54 cm   1 kg ≈ 2.2 lb
🧠

Key Words — What Do They Mean?

Cross-systemConverting between
two systems
MethodWrite: X units × conversion factor = Y units. Arrange to solve for what you need.
Visual ScaleHow imperial and metric lengths compare — shown as bars
1 inch = 2.54 centimetres 1 in 2.54 cm ← same length! 1 foot reference = 648px wide 1 foot = 30.48 centimetres (≈ 30 cm) 1 foot (12 inches) 30.48 cm (≈ the same length) 1 mile vs 1 kilometre (1 mile = 1.609 km) 1 mile 1 km (about 62% of a mile) ← remaining 0.609 km →
Conversion Reference TableThe key conversion factors — memorise these!
QuantityImperial → MetricMetric → Imperial
Length1 inch = 2.54 cm1 cm = 0.394 inches
Length1 foot = 30.48 cm = 0.305 m1 m = 3.281 feet
Length1 mile = 1.609 km1 km = 0.621 miles
Length1 yard = 0.914 m1 m = 1.094 yards
Mass1 ounce (oz) = 28.35 g1 g = 0.035 oz
Mass1 pound (lb) = 453.6 g = 0.454 kg1 kg = 2.205 lb
Mass1 imperial ton = 1016 kg1 tonne = 0.984 imp. ton
Volume1 pint = 568 ml1 litre = 1.76 pints
Volume1 gallon = 4.546 litres1 litre = 0.220 gallons
Convert 5 feet 8 inches to metres
Total inches: 5×12 + 8 = 68 inches
× 2.54: 68 × 2.54 = 172.72 cm
Answer: 1.727 m ✅
⚙️ Convert 3.5 kg to pounds (lbs)
Factor: 1 kg = 2.205 lb
Multiply: 3.5 × 2.205 = 7.7175
Answer: 7.72 lb (3 s.f.) ✅
🔄 Try it — Metric ↔ ImperialLength · Mass · Volume
👆Try: 5 ft → m · 3.5 kg → lb · 26.2 miles → km (marathon) · 1 gallon → L
🌡️

Temperature Conversions

Three scales — Celsius (°C), Fahrenheit (°F) and Kelvin (K). Engineers use all three depending on the application.

📋 Temperature — Quick Reference

1
°F = (°C × 9/5) + 32
2
K = °C + 273
🧠

Key Words — What Do They Mean?

KelvinStarts at
absolute zero
Three Temperature ScalesKey reference points shown visually
BOILING FREEZING °C Celsius 100°C boiling 37°C body temp 0°C freezing °F Fahrenheit 212°F boiling 98.6°F body 32°F freezing K Kelvin 373 K boiling 310 K body 273 K freezing Absolute zero: 0 K = −273.15°C = −459.67°F (below this diagram)
°C ↔ °F Formulas
°F = (°C × 9/5) + 32
°C = (°F − 32) × 5/9
Convert 25°C to °F
Formula: °F = (25 × 9/5) + 32
Calculate: (25 × 1.8) + 32 = 45 + 32
Answer: 77°F ✅
°C ↔ Kelvin
K = °C + 273.15
°C = K − 273.15
📌 Kelvin is used in thermodynamics formulas (e.g. ideal gas law: PV = nRT). Temperature differences are the same in K and °C — only the zero point shifts.
Convert 350°C to Kelvin
Formula: K = 350 + 273.15
Answer: 623.15 K ✅
🌡️ Try it — Temperature Converter°C · °F · K
→
👆Try: 25°C → °F · 350°C → K · 150°C → K (gas law) · 212°F → °C
💡 Quick memory: °C to K — just add 273. K to °C — just subtract 273. The 0.15 is only needed for high-precision work.
⚙️

Applications

Where this topic is used in engineering, manufacturing, maintenance and daily life.

🧠

Where You'll See Units

DrawingsDimensions in
mm
RecipesGrams,
litres
⚙️

Units in Engineering

Every engineering calculation involves units. Here's where you'll actually need each conversion skill in your exam and on the job.

📋 Engineering Units — Quick Reference

1
Always check units match before calculating
2
Force (N), Pressure (Pa), Power (W), Speed (m/s)
🧠

Key Words — What Do They Mean?

ConsistencyAll values in
matching units

🔩 Precision Machining

Drawings may mix inches and mm. CNC programs work in mm. A 3/8" drill bit = 3/8 × 25.4 = 9.525 mm. Thread pitch M8 = 1.25 mm = 1.25 × 0.0394 = 0.049 inches.

3/8" drill bit:
3 ÷ 8 = 0.375 inches
0.375 × 25.4 = 9.525 mm

M8 pitch = 1.25 mm
= 1.25 ÷ 25.4 = 0.0492"

⚡ Electrical Engineering

Voltage, current and resistance use SI prefixes constantly. A 4.7 kΩ resistor = 4700 Ω. A 100 μF capacitor = 0.0001 F.

4.7 kΩ = 4.7 × 10³ = 4700 Ω
47 mA = 47 × 10⁻³ = 0.047 A
V = IR = 0.047 × 4700
= 220.9 V

🏗️ Structural Engineering

Forces in kN, stresses in MPa or N/mm² (same thing!), Young's modulus in GPa. Unit consistency in stress calculations is critical.

Stress = Force ÷ Area
F = 4.5 kN = 4500 N
A = 300 mm²
σ = 4500 ÷ 300 = 15 N/mm²
= 15 MPa

🌡️ Thermodynamics

Heat engines, refrigerators and gas laws all use Kelvin. Thermal expansion coefficients use 1/°C or 1/K (same difference in change).

Ideal gas: PV = nRT
T must be in KELVIN
T = 150°C + 273 = 423 K

Expansion: ΔL = L × α × ΔT
ΔT same in °C or K
🔧 Engineering Example — Unit Consistency Check
Problem: Calculate the pressure (Pa) on a piston. Force = 2.4 kN, area = 0.008 m².
Convert: 2.4 kN = 2.4 × 1000 = 2400 N
Formula: P = F ÷ A = 2400 ÷ 0.008
Answer: P = 300,000 Pa = 300 kPa = 0.3 MPa ✅
⚙️ Try it — Engineering Unit ConverterForce · Pressure · Power · Speed
👆Try: 2.4 kN → N · 300000 Pa → kPa · 70 mph → m/s · 1 kWh → J
🎮

Quick Fire Quiz

10 questions, instant feedback.

⚡ Quick Blitz

Score: 0Streak: 0 🔥Q 1/10
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📝

Practice Questions

15 questions in 3 tiers — Level 2 Engineering style with full working shown.

🟢 Tier 1 — Foundations
Q1
State the SI unit and symbol for: (a) force   (b) pressure   (c) power
[3]
(a) Newton (N)
(b) Pascal (Pa)
(c) Watt (W)
Q2
Convert: (a) 4.5 km to m   (b) 850 mm to m   (c) 2.3 cm to mm
[3]
(a) 4.5 × 1000 = 4500 m
(b) 850 ÷ 1000 = 0.85 m
(c) 2.3 × 10 = 23 mm
Q3
Convert: (a) 3.2 kg to g   (b) 750 g to kg
[2]
(a) 3.2 × 1000 = 3200 g
(b) 750 ÷ 1000 = 0.75 kg
Q4
Write the prefix and symbol for: (a) × 10⁻³   (b) × 10³   (c) × 10⁶
[3]
(a) milli, m
(b) kilo, k
(c) Mega, M
Q5
Convert 25°C to (a) Fahrenheit   (b) Kelvin
[3]
(a) °F = (25 × 9/5) + 32 = 45 + 32 = 77°F
(b) K = 25 + 273.15 = 298.15 K
🟡 Tier 2 — Core Skills
Q6
Convert 47 mA to amperes, then to μA.
[3]
47 mA = 47 × 10⁻³ = 0.047 A
0.047 A = 0.047 × 10⁶ μA = 47,000 μA
Q7
A component is 3.5 inches long. Convert to mm. (1 inch = 25.4 mm)
[2]
3.5 × 25.4 = 88.9 mm ✅
Q8
Convert 5 feet 4 inches to centimetres. (1 inch = 2.54 cm)
[3]
Total inches = 5×12 + 4 = 64 inches
64 × 2.54 = 162.56 cm ✅
Q9
Convert an area of 2.5 m² to cm².
[3]
Remember: 1 m = 100 cm, so 1 m² = 100² cm²
1 m² = 10,000 cm²
2.5 × 10,000 = 25,000 cm² ✅
Q10
Convert 350°F to Celsius.
[2]
°C = (350 − 32) × 5/9 = 318 × 5/9 = 1590/9 = 176.7°C ✅
🔴 Tier 3 — Extension Challenge
Q11
Calculate the stress on a bolt. Force = 8.5 kN, cross-sectional area = 50 mm². Express the answer in (a) N/mm²   (b) MPa   (c) Pa in standard form.
[5]
F = 8.5 kN = 8500 N
σ = F/A = 8500 ÷ 50 = 170 N/mm²
(a) 170 N/mm²
(b) 170 MPa (1 N/mm² = 1 MPa)
(c) 170 × 10⁶ Pa = 1.70 × 10⁸ Pa ✅
Q12
An engineer in the USA specifies a shaft diameter of 1.375 inches. The UK workshop works in mm. Convert to mm to 2 decimal places. (1 inch = 25.4 mm)
[3]
1.375 × 25.4 = 34.93 mm ✅
Q13
A steel bar is heated from 20°C to 680°C. The coefficient of linear thermal expansion is 12 × 10⁻⁶ /K. The bar is 2.4 m long. Calculate the extension in mm.
[4]
ΔT = 680 − 20 = 660 K
ΔL = L × α × ΔT
= 2.4 × 12×10⁻⁶ × 660
= 0.019008 m
= 19.0 mm ✅
Q14
A fuel tank holds 45 gallons. Calculate its capacity in (a) litres and (b) cm³. (1 gallon = 4.546 litres)
[4]
(a) 45 × 4.546 = 204.57 litres
(b) 204.57 × 1000 = 204,570 cm³ ✅
Q15
An electric motor outputs 2.2 kW at 1450 rpm. Calculate the shaft torque using T = P / ω where ω = 2πn/60. Show all unit conversions.
[5]
P = 2.2 kW = 2200 W
ω = 2π × 1450 ÷ 60 = 151.84 rad/s
T = 2200 ÷ 151.84
= 14.49 N·m ✅
🎯 Score guide: Q1–5 = foundations (14 marks) · Q6–10 = core skills (13 marks) · Q11–15 = extension challenge (21 marks)
SL

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